Optimal. Leaf size=143 \[ \frac{a^3}{8 d (a-a \sin (c+d x))^2}+\frac{a^2}{d (a-a \sin (c+d x))}+\frac{a^2}{8 d (a \sin (c+d x)+a)}-\frac{a \csc ^2(c+d x)}{2 d}-\frac{a \csc (c+d x)}{d}-\frac{39 a \log (1-\sin (c+d x))}{16 d}+\frac{3 a \log (\sin (c+d x))}{d}-\frac{9 a \log (\sin (c+d x)+1)}{16 d} \]
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Rubi [A] time = 0.132132, antiderivative size = 143, normalized size of antiderivative = 1., number of steps used = 4, number of rules used = 3, integrand size = 27, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.111, Rules used = {2836, 12, 88} \[ \frac{a^3}{8 d (a-a \sin (c+d x))^2}+\frac{a^2}{d (a-a \sin (c+d x))}+\frac{a^2}{8 d (a \sin (c+d x)+a)}-\frac{a \csc ^2(c+d x)}{2 d}-\frac{a \csc (c+d x)}{d}-\frac{39 a \log (1-\sin (c+d x))}{16 d}+\frac{3 a \log (\sin (c+d x))}{d}-\frac{9 a \log (\sin (c+d x)+1)}{16 d} \]
Antiderivative was successfully verified.
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Rule 2836
Rule 12
Rule 88
Rubi steps
\begin{align*} \int \csc ^3(c+d x) \sec ^5(c+d x) (a+a \sin (c+d x)) \, dx &=\frac{a^5 \operatorname{Subst}\left (\int \frac{a^3}{(a-x)^3 x^3 (a+x)^2} \, dx,x,a \sin (c+d x)\right )}{d}\\ &=\frac{a^8 \operatorname{Subst}\left (\int \frac{1}{(a-x)^3 x^3 (a+x)^2} \, dx,x,a \sin (c+d x)\right )}{d}\\ &=\frac{a^8 \operatorname{Subst}\left (\int \left (\frac{1}{4 a^5 (a-x)^3}+\frac{1}{a^6 (a-x)^2}+\frac{39}{16 a^7 (a-x)}+\frac{1}{a^5 x^3}+\frac{1}{a^6 x^2}+\frac{3}{a^7 x}-\frac{1}{8 a^6 (a+x)^2}-\frac{9}{16 a^7 (a+x)}\right ) \, dx,x,a \sin (c+d x)\right )}{d}\\ &=-\frac{a \csc (c+d x)}{d}-\frac{a \csc ^2(c+d x)}{2 d}-\frac{39 a \log (1-\sin (c+d x))}{16 d}+\frac{3 a \log (\sin (c+d x))}{d}-\frac{9 a \log (1+\sin (c+d x))}{16 d}+\frac{a^3}{8 d (a-a \sin (c+d x))^2}+\frac{a^2}{d (a-a \sin (c+d x))}+\frac{a^2}{8 d (a+a \sin (c+d x))}\\ \end{align*}
Mathematica [C] time = 0.753603, size = 86, normalized size = 0.6 \[ -\frac{a \csc (c+d x) \, _2F_1\left (-\frac{1}{2},3;\frac{1}{2};\sin ^2(c+d x)\right )}{d}-\frac{a \left (2 \csc ^2(c+d x)-\sec ^4(c+d x)-4 \sec ^2(c+d x)-12 \log (\sin (c+d x))+12 \log (\cos (c+d x))\right )}{4 d} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.112, size = 151, normalized size = 1.1 \begin{align*}{\frac{a}{4\,d\sin \left ( dx+c \right ) \left ( \cos \left ( dx+c \right ) \right ) ^{4}}}+{\frac{5\,a}{8\,d\sin \left ( dx+c \right ) \left ( \cos \left ( dx+c \right ) \right ) ^{2}}}-{\frac{15\,a}{8\,d\sin \left ( dx+c \right ) }}+{\frac{15\,a\ln \left ( \sec \left ( dx+c \right ) +\tan \left ( dx+c \right ) \right ) }{8\,d}}+{\frac{a}{4\,d \left ( \sin \left ( dx+c \right ) \right ) ^{2} \left ( \cos \left ( dx+c \right ) \right ) ^{4}}}+{\frac{3\,a}{4\,d \left ( \sin \left ( dx+c \right ) \right ) ^{2} \left ( \cos \left ( dx+c \right ) \right ) ^{2}}}-{\frac{3\,a}{2\,d \left ( \sin \left ( dx+c \right ) \right ) ^{2}}}+3\,{\frac{a\ln \left ( \tan \left ( dx+c \right ) \right ) }{d}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 1.13342, size = 171, normalized size = 1.2 \begin{align*} -\frac{9 \, a \log \left (\sin \left (d x + c\right ) + 1\right ) + 39 \, a \log \left (\sin \left (d x + c\right ) - 1\right ) - 48 \, a \log \left (\sin \left (d x + c\right )\right ) + \frac{2 \,{\left (15 \, a \sin \left (d x + c\right )^{4} - 3 \, a \sin \left (d x + c\right )^{3} - 22 \, a \sin \left (d x + c\right )^{2} + 4 \, a \sin \left (d x + c\right ) + 4 \, a\right )}}{\sin \left (d x + c\right )^{5} - \sin \left (d x + c\right )^{4} - \sin \left (d x + c\right )^{3} + \sin \left (d x + c\right )^{2}}}{16 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] time = 1.58582, size = 733, normalized size = 5.13 \begin{align*} \frac{30 \, a \cos \left (d x + c\right )^{4} - 16 \, a \cos \left (d x + c\right )^{2} + 48 \,{\left (a \cos \left (d x + c\right )^{4} - a \cos \left (d x + c\right )^{2} -{\left (a \cos \left (d x + c\right )^{4} - a \cos \left (d x + c\right )^{2}\right )} \sin \left (d x + c\right )\right )} \log \left (\frac{1}{2} \, \sin \left (d x + c\right )\right ) - 9 \,{\left (a \cos \left (d x + c\right )^{4} - a \cos \left (d x + c\right )^{2} -{\left (a \cos \left (d x + c\right )^{4} - a \cos \left (d x + c\right )^{2}\right )} \sin \left (d x + c\right )\right )} \log \left (\sin \left (d x + c\right ) + 1\right ) - 39 \,{\left (a \cos \left (d x + c\right )^{4} - a \cos \left (d x + c\right )^{2} -{\left (a \cos \left (d x + c\right )^{4} - a \cos \left (d x + c\right )^{2}\right )} \sin \left (d x + c\right )\right )} \log \left (-\sin \left (d x + c\right ) + 1\right ) + 2 \,{\left (3 \, a \cos \left (d x + c\right )^{2} + a\right )} \sin \left (d x + c\right ) - 6 \, a}{16 \,{\left (d \cos \left (d x + c\right )^{4} - d \cos \left (d x + c\right )^{2} -{\left (d \cos \left (d x + c\right )^{4} - d \cos \left (d x + c\right )^{2}\right )} \sin \left (d x + c\right )\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.34488, size = 169, normalized size = 1.18 \begin{align*} -\frac{36 \, a \log \left ({\left | \sin \left (d x + c\right ) + 1 \right |}\right ) + 156 \, a \log \left ({\left | \sin \left (d x + c\right ) - 1 \right |}\right ) - 192 \, a \log \left ({\left | \sin \left (d x + c\right ) \right |}\right ) - \frac{4 \,{\left (9 \, a \sin \left (d x + c\right ) + 11 \, a\right )}}{\sin \left (d x + c\right ) + 1} + \frac{27 \, a \sin \left (d x + c\right )^{4} + 74 \, a \sin \left (d x + c\right )^{3} - 141 \, a \sin \left (d x + c\right )^{2} + 32 \, a}{{\left (\sin \left (d x + c\right )^{2} - \sin \left (d x + c\right )\right )}^{2}}}{64 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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